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\r\n \r\n i have the following date vaidation regex pattern:
\r\n[0-3]\\d-(JAN|FEB|
\r\nMAR|APR|MAY|JUN|J UL|
\r\nAUG|SEP|OCT|NOV|D EC)
\r\n-\\d{4}
\r\n
\r\ni now its fine...i think that the days pattern is somewhat wrong isnt it?
\r\ni mean you can enter nubers bigger then 31 right?
\r\nso any idea how to fix it????\r\n
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\r\n\r\n\r\n\r\n\r\n\r\n\r\n\r\n \r\n \r\n \r\n \r\n\r\n\r\n\r\n\r\n'; pd[426933] = '\r\n\r\n \r\n\r\n
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\r\n Originally Posted by John_0025\r\n \r\n
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It would also match 00 as the day and allow some unrealistic years (actually depends what you are doing. Anyway show how to only allow year 19xx or 20xx)
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Code:
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(0[1-9]|[12][0-9]|3[01])-(JAN|FEB|MAR|APR|MAY|JUN|JUL|AUG|SEP|OCT|NOV|DEC)-(19|20)\\d\\d
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sweeeeeeet!!! thanx again mate!
\r\nim starting to understand this regexp thingy....(heared about it only before 2 days ago) \r\n
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\r\n\r\n\r\n\r\n'; // next/previous post info pn[426921] = "426937,426933"; pn[0] = ",426921"; pn[426933] = "426921,426937"; pn[426937] = "426933,426921"; // cached usernames pu[0] = guestphrase; pu[36445] = "FlyBoy"; pu[35515] = "John_0025"; // -->
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Old 09-07-2004, 09:21 AM
FlyBoy FlyBoy is offline
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Join Date: Sep 2004
Posts: 106
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Default date validation.
i have the following date vaidation regex pattern:
[0-3]\d-(JAN|FEB|
MAR|APR|MAY|JUN|J UL|
AUG|SEP|OCT|NOV|D EC)
-\d{4}

i now its fine...i think that the days pattern is somewhat wrong isnt it?
i mean you can enter nubers bigger then 31 right?
so any idea how to fix it????
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